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A prairie dog left its burrow 5 feet underground and started digging deeper into the ground. It digs straight down at a constant rate of 2
feet per minute.
How long does it take the prairie dog to reach 13 feet underground?
Enter your answer in the box
min

Willing to give Brainliest No Links

A Prairie Dog Left Its Burrow 5 Feet Underground And Started Digging Deeper Into The Ground It Digs Straight Down At A Constant Rate Of 2 Feet Per Minute How Lo class=

Sagot :

Building and solving an equation to model the situation, it is found that it takes 4 min for the prairie dog to reach 13 feet underground.

  • Initially, the dog is 5 feet underground.
  • Each minute, the dog goes 2 more feet underground.

Hence, the underground height of the dog after t seconds is given by:

[tex]h(t) = 5 + 2t[/tex]

The time it takes for the dog to reach 13 feet underground is t for which h(t) = 13, hence:

[tex]h(t) = 5 + 2t[/tex]

[tex]13 = 5 + 2t[/tex]

[tex]2t = 8[/tex]

[tex]t = \frac{8}{2}[/tex]

[tex]t = 4[/tex]

It takes 4 min for the prairie dog to reach 13 feet underground.

A similar problem is given at brainly.com/question/25290003

JoanYau

Answer:

4min

The answer is of K12

Step-by-step explanation:

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