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Step-by-step explanation:

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abidemiokin

The polynomial whole zeros are  α+β and  αβ is  x^2 + x - 12

Given the quadratic equation x^2 - 3x - 4 = 0

From the equation, a = 1, b = -3 and c = -4

The sum of the equation α+β = -b/a

α+β = 3/1 = 3

The product of the equation αβ = c/a

αβ = -4/1 = -4

Get the polynomial equation with zeros of 3 and -4

f(x) = (x-3)(x+4)

f(x)= x^2 + 4x - 3x - 12

f(x) = x^2 + x - 12

Hence the polynomial whole zeros are  α+β and  αβ is  x^2 + x - 12

Learn more on roots of quadratic equations here: https://brainly.com/question/776122

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