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During the hammer throw at a track meet, an 8.0 kg hammer is accidentally thrown straight up. If 784.0 J of
work were done on the hammer to give it vertical velocity, how high will it rise?


Sagot :

The height risen by the hammer when the work were done is 10 m.

The given parameters;

  • Mass of the hammer, m = 8.0 kg
  • Work done on the hammer, W = 780 J

Apply work energy - theorem to determine the height risen by the hammer when the work is done on it;

[tex]E = mgh\\\\h = \frac{E}{mg} \\\\h = \frac{784}{8 \times 9.8} \\\\h = 10 \ m[/tex]

Thus, the height risen by the hammer when the work were done is 10 m.

Learn more about work-energy theorem here: https://brainly.com/question/22236101