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Suppose that a report by a leading medical organization claims that the healthy human heart beats an average of 7272 times per minute. Advances in science have led some researchers to question if the healthy human heart beats an entirely different amount of time, on average, per minute. They obtain pulse rate data from a sample of 8585 healthy adults and find the average number of heart beats per minute to be 76,76, with a standard deviation of 13.13. Before conducting a statistical test of significance, this outcome needs to be converted to a standard score, or a test statistic. What would that test statistic be

Sagot :

Using the t-distribution, the test statistic is of t = 2.84.

We have the standard deviation for the sample, thus, the t-distribution is used. The test statistic is given by:

[tex]t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}[/tex]

The parameters are:

  • [tex]\overline{x}[/tex] is the sample mean.
  • [tex]\mu[/tex] is the value tested.
  • s is the standard deviation of the sample.
  • n is the sample size.

In this problem, the values of the parameters are: [tex]\overline{x} = 76, \mu = 72, s = 13, n = 85[/tex]

Hence:

[tex]t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}[/tex]

[tex]t = \frac{76 - 72}{\frac{13}{\sqrt{85}}}[/tex]

[tex]t = 2.84[/tex]

The test statistic is t = 2.84.

A similar problem is given at https://brainly.com/question/25703221

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