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A population is normally distributed with mean 36.3 and standard deviation 0.5. Find the following probability. (Round your answer to four decimal places.) p( 36.3 < x < 36.8 )

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abidemiokin

The probability value for the normal distribution is between 0 and 1 that is 0<Pr<0.3413

First, we need to get the z-value for both x-values

The formula for calculating the z-score is expressed as:

[tex]z=\frac{x-\mu}{\sigma}[/tex]

If x = 36.3

[tex]z=\frac{36.3-36.3}{0.5}\\z=\frac{0}{0.5}\\z=0[/tex]

Similarly, if x = 36.8

[tex]z=\frac{36.8-36.3}{0.5}\\z=\frac{0.5}{0.5}\\z=1.0[/tex]

This shows that the z-value for the normal distribution is between 0 and 1 that is 0<z<1

The probability value for the normal distribution is between 0 and 1 that is 0<Pr<0.3413

Learn more on normal distribution here: https://brainly.com/question/23418254

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