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A 10. kilogram wood box is at rest on a wood floor.  When a horizontal force is applied on the box toward the right, the box begins to gain speed at a constant, steady rate.  After a period of 5.0 seconds, the box has attained a velocity of 20. m/s.  What is the magnitude of the applied force?

Sagot :

onyebuchinnaji

The magnitude of the applied force on the wood box is 40 N.

The given parameters;

  • mass of the wood box, m = 10 kg
  • initial velocity, u = 0
  • time of motion, t = 5 s
  • final velocity, v = 20 m/s

The acceleration of the wood box is calculated as follows;

[tex]a = \frac{v-u}{t} \\\\a = \frac{20 - 0}{5} \\\\a = 4 \ m/s^2[/tex]

The magnitude of the applied force on the wood box is calculated as follows;

[tex]F = ma\\\\F = 10 \times 4\\\\F = 40 \ N[/tex]

Learn more here about applied force here:https://brainly.com/question/2733221

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