in order for a population to remain in hardy-weinberg equilibrium, mating must be random. what would happen to the genotypic and phenotypic frequencies if individuals were more likely to mate with others that shared their phenotype?

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03-12-2021
Biology

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in order for a population to remain in hardy-weinberg equilibrium, mating must be random. what would happen to the genotypic and phenotypic frequencies if individuals were more likely to mate with others that shared their phenotype?

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marianaegarciaperedo marianaegarciaperedo · Answer 1 · 2021-12-09T22:04:59-05:00

If the assumption of random matings is not accomplished, and individuals mate by similar phenotype, the involved phenotype and the h0m0zyg0us genotypes would increase their frequencies.

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If individuals in a population were more likely to mate with others that shared their phenotype, the genotypic and phenotypic frequencies would change.

The assumption of random mating would not be accomplished, because individuals would rather mate with other individuals that look like them.

This is known as matings by similar phenotype.

Individuals with similar phenotypes in a certain characteristic are more likely to mate than expected matings by chance.

Individuals choose partners with phenotypes similar to their own.

Allelic frequencies do not change. However, mating by similar phenotype will cause,

Disequilibrium in the gametic phase

Increase in h0m0zyg0us genotypes at heter0zyg0us expense in loci that determine the selected trait.

Separation of the population into genetically distinct subgroups

concerning the involved loci.

Increase in the phenotypic frequency.

Matings by similar phenotype might be an important factor in the process speciation, leading to evolution.

So, if individuals were more likely to mate with others that shared their phenotype, the phenotypic frequency would increase as well as the h0m0zyg0us genotypes.

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