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Given right triangle MNL, what is the value of cos(M)? Three-fifths Three-fourths Four-fifths Five-thirds

Sagot :

akposevictor

By applying the Pythagorean Theorem and the Trigonometry ratio, CAH, the value of cos(M) = 4/5

Recall:

Trigonometry ratios, SOH CAH TOA can be applied to solve a right triangle.

  • Pythagorean Theorem can also be applied which is: c² = b² + a², where c is the longest side (hypotenuse length).

Given:

ΔMNL is a right triangle

ML = 25

NL = 15

Find MN using the Pythagorean Theorem:

MN = √(ML² - NL²)

MN = √(25² - 15²)

MN = 20

To find the value of cos(M), apply the trigonometry ratio, CAH, which is:

cos ∅ = Adj/Hyp

  • Where,

∅ = M (reference angle)

Hypotenuse = ML = 25

Adjacent = MN = 20

  • Plug in the values:

cos(M) = 20/25

cos(M) = 4/5

Learn more about Trigonometry ratios on:

https://brainly.com/question/10417664

View image akposevictor
pleaseoverstay

Answer:

C 4/5s

Step-by-step explanation:

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