Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Get detailed and accurate answers to your questions from a community of experts on our comprehensive Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

2. The volume of gas in a container at a constant temperature varies inversely as the pressure.
(a) If the volume is 26 cubic centimeters at a pressure of 6 pounds, write an equation to represent this relationship.
Show work!! (3 points)
(b) Use your equation from part a to find the volume of a gas that has a pressure of 17. Round your answer to the
nearest hundredth if necessary. Show work!! (2 points work, 1-point answer)


Sagot :

[tex]\qquad \qquad \textit{inverse proportional variation} \\\\ \textit{\underline{y} varies inversely with \underline{x}} ~\hspace{6em} \stackrel{\textit{constant of variation}}{y=\cfrac{\stackrel{\downarrow }{k}}{x}~\hfill } \\\\ \textit{\underline{x} varies inversely with }\underline{z^5} ~\hspace{5.5em} \stackrel{\textit{constant of variation}}{x=\cfrac{\stackrel{\downarrow }{k}}{z^5}~\hfill } \\\\[-0.35em] \rule{34em}{0.25pt}[/tex]

[tex]\stackrel{\textit{\boxed{v}olume varies inverse as the \boxed{p}ressure}}{v = \cfrac{k}{p}}\qquad \textit{we also know that} \begin{cases} v = \stackrel{cm^3}{26}\\ p=\stackrel{lbs}{6} \end{cases} \\\\\\ 26=\cfrac{k}{6}\implies 156=k~\hfill \underset{\textit{part a)}}{\boxed{v = \cfrac{156}{p}}} \\\\\\ \textit{when p = 17, what is "v"?}\qquad v = \cfrac{156}{17}\implies v = 9\frac{3}{17}\implies \underset{\textit{part b)}}{v\approx 9.18~cm^3}[/tex]

We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.