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Someone pls help: Find the slope of the line described by

3y = x + 6. Thanks! I will give brainiest

Sagot :

Answer:

1/3.

Step-by-step explanation:

[tex]3y=x+6[/tex]

The first thing to do is to get this equation in slope-intercept form. First divide both sides by 3, then simplify it down to slope intercept form ( [tex]y=mx+b[/tex] ):

[tex]y=\frac{x+6}{3}\\\\y=\frac{x}{3}+2\\\\y=\frac{1}{3}x+2[/tex]

Here, the slope is 1/3.

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