braydengodfrey
Answered

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Write an equation of the line in point-slope form that is perpendicular to the given line
and passes through the given point.
y = −3x + 4; (−1, 3)

Sagot :

cinderofsoulsss

Answer:

[tex]y-3=\frac{1}{3}(x+1)[/tex]

Step-by-step explanation:

The slope of a perpendicular line is the negative reciprocal of the original slope. Here, it's -3 and 1/3. Another example would be 2 and -1/2.

Next, point slope form is:

[tex](y-y_1)=m(x-x_1)[/tex]

where m is the slope and (x1, y1) is any point on the line.

We're given that point, and we've found the slope above, so the equation is:

[tex]y-3=\frac{1}{3}(x+1)[/tex]

View image cinderofsoulsss
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