Answered

Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Our platform provides a seamless experience for finding precise answers from a network of experienced professionals. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

Consider the following reaction:
Mg(s) + 2HCl(aq)
->
MgCl2 (aq) +H2(8)

If 0.475 g Mg reacts with 124.95 mL of 1.08 M HCl, how many mol of H2 gas will be produced?

Calculate the initial moles of Mg and HCl and find the limiting reactant?

Sagot :

torrisjossi

Answer:The balanced equation of Mg(s) + 2HCl(aq) ==> MgCl2(aq) + H2(g) does NOT tell you how many moles of Mg or H2 are present.  It only tells you the MOLE RATIO of the reactants and products.  Thus, 1 mole Mg reacts with 2 moles HCl to produce 1 mole of hydrogen gas.

Explanation:The balanced equation of Mg(s) + 2HCl(aq) ==> MgCl2(aq) + H2(g) does NOT tell you how many moles of Mg or H2 are present.  It only tells you the MOLE RATIO of the reactants and products.  Thus, 1 mole Mg reacts with 2 moles HCl to produce 1 mole of hydrogen gas.

Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.