Answered

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write an equation that is perpendicular to y=3/5x-1 and passes through the point (9,14)

Sagot :

mxrxxn

Answer:

y=(-5/3)x+29

Step-by-step explanation:

we will use the base formula y=mx+b

In order to be perpendicular, the slope must be the flipped fraction and have the opposite sign, so our m is (-5/3)

y=(-5/3)x+b

You can plug in the (9,14) point in order to find the b

14=(-5/3)(9)+b

14=(-45/3)+b

14=(-15)+b

14+15=b

29=b

and so altogether our equation is y=(-5/3)x+29

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