Answered

Welcome to Westonci.ca, where your questions are met with accurate answers from a community of experts and enthusiasts. Join our platform to connect with experts ready to provide precise answers to your questions in different areas. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

The diagram below shows a 5.0-kilogram mass sliding 9.0 meters down an incline from a height of
2.0 meters in 3.0 seconds. The object gains 90. joules of kinetic energy while sliding.
How much work is done against friction as the mass slides the 9.0 meters?

Sagot :

onyebuchinnaji

The work done against friction as the mass slides is 8 J.

The given parameters:

  • sliding mass, m = 5.0 kg
  • distance traveled by the mass, s = 9.0 m
  • height of incline, h = 2.0 m
  • time of motion, t = 3.0 s
  • kinetic energy of the object, K.E = 90 J

The work done against friction as the mass slides can be determined by applying work-energy theorem.

[tex]\Delta E= W\\\\P.E - K.E = W[/tex]

the change in mechanical energy of the sliding mass, is equal to energy lost to friction.

[tex]W = P.E - K.E\\\\W = mgh - K.E\\\\W = (5 \times 9.8 \times 2) - 90\\\\W = 98 - 90\\\\W = 8 \ J[/tex]

Thus, the work done against friction as the mass slides is 8 J.

Learn more about work-energy theorem here:https://brainly.com/question/10063455

Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.