Welcome to Westonci.ca, where your questions are met with accurate answers from a community of experts and enthusiasts. Discover comprehensive answers to your questions from knowledgeable professionals on our user-friendly platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
[tex]~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\dotfill&\$1400\\ P=\textit{original amount deposited}\dotfill &\$1100\\ r=rate\to r\%\to \frac{r}{100}\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\dotfill &12\\ t=years\dotfill &7 \end{cases}[/tex]
[tex]1400=1100\left( 1+\frac{r}{12} \right)^{12\cdot 7}\implies \cfrac{1400}{1100}=\left( 1+\frac{r}{12} \right)^{84}\implies \cfrac{14}{11}=\left( 1+\frac{r}{12} \right)^{84} \\\\\\ \sqrt[84]{\cfrac{14}{11}}=1+\cfrac{r}{12}\implies \sqrt[84]{\cfrac{14}{11}}-1=\cfrac{r}{12}\implies 12\left[ \sqrt[84]{\cfrac{14}{11}}-1 \right]=r \\\\\\ 0.0345\approx r\stackrel{\textit{converting to \%}}{0.0345\cdot 100}\implies 3.45\approx r\implies \stackrel{\textit{rounded up}}{3.4\approx r}[/tex]
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.