Answered

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Write a quadratic equation having the given numbers as solutions.
- 3 and - 1

Sagot :

[tex]\begin{cases}x = -3\implies &x+3=0\\x = -1\implies &x+1=0\end{cases}~\hfill \begin{array}{llll}\stackrel{~\hfill \textit{original equation}}{(x+3)(x+1)=0}\\\\\stackrel{using~\mathbb{FOIL}}{x^2+4x+3 = y}\end{array}[/tex]

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