gracemacias347
Answered

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A 3,65 kg mass attached to a
light string rotates on a
horizontal, frictionless table. The
radius of the circle is 1.21 m, and
the string can support a mass of
32.4 kg before breaking. The
acceleration of gravity is
9.8m/s2. What maximum
speed can the mass have before
the string breaks?
S

Sagot :

hamzaahmeds

This question involves the concepts of tension, weight, and centripetal force.

The maximum speed, the mass can have before the string breaks is "10.26 m/s".

First, we will find the maximum tension force:

Tension = Weight

T = W = mg = (32.4 kg)(9.81 m/s²)

T = 317.84 N

Now, this tension force must be equal to the centripetal force:

[tex]T = \frac{mv^2}{r}\\v=\sqrt{\frac{Tr}{m}}[/tex]

where,

v = maximum speed = ?

r = radius = 1.21 m

m = mass = 3.65 kg

Therefore,

[tex]v=\sqrt{\frac{(317.84\ N)(1.21\ m)}{3.65\ kg}}\\[/tex]

v = 10.26 m/s

Learn more about centripetal force here:

brainly.com/question/11324711?referrer=searchResults

The attached picture shows the centripetal force.

View image hamzaahmeds
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