Queenbre1234
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Which number is divisibly by both 3 and 4

A) 101.444

B) 112436

C)118,754

D) 118,422​

Sagot :

Spectrier

Divisibility rule of 3:

If the sum of the digits are divisible by three, the number is divisible

Divisibility rule of 4:

If the last two digits are divisibly by four, it's divisible

Now let's apply the divisibility rule with the numbers

A) 101.444/3 = 33.1846666...

So it's clearly not divisible by three

B) 112436/3 = 37478.6666...

Not divisible by three either

C) 118754/3 = 39584.6666...

Nope.

D) 118422/3 = 39474

We found one that is divisible, so now we divide it by four

We take the last two digits and divide it with four

22/4 = 5.5

Therefore, the answer is D, because it ends with quotients that doesn't repeat

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