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plzz help asap rewrite the equation to the form ax^2+bx+c=0: x^2+(1-x)(1-3x)=x

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Answer:

[tex]4x^2 - 5x + 1 = 0[/tex]

Step-by-step explanation:

[tex]x^2+(1-x)(1-3x)=x\\x^2+(1-x)(1-3x) - x = 0\\x^2+ 3x^2 - 4x + 1 - x = 0\\\\[/tex]

4x^2 - 5x + 1 = 0

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