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Sagot :
The mass (in grams) of the silicon present in the computer chip is 2.19 g
From Avogadro's hypothesis,
6.02×10²³ atoms = 1 mole of Si
But
1 mole of Si = 28 g
Thus, we can say that:
6.02×10²³ atoms = 28 g of Si
- With the above information, we can obtain the mass of silicon, Si present in the computer chip. This can be obtained:
6.02×10²³ atoms = 28 g of Si
Therefore,
4.71×10²² atoms = (4.71×10²² × 28) / 6.02×10²³ g of Si
4.71×10²² atoms = 2.19 g of Si
Thus, the mass of silicon, Si present in the computer chip is 2.19 g
Learn more on Avogadro's number: https://brainly.com/question/25811549
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