Answered

At Westonci.ca, we provide reliable answers to your questions from a community of experts. Start exploring today! Ask your questions and receive detailed answers from professionals with extensive experience in various fields. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

Please solve this for me with full steps please it’s urgent
Don’t spam or write unnecessary things or else I’ll report

Please Solve This For Me With Full Steps Please Its Urgent Dont Spam Or Write Unnecessary Things Or Else Ill Report class=

Sagot :

Answer:

Step-by-step explanation:

logx[tex]y^{2}[/tex] <=> logx + 2logy = a (1)

log[tex]x^{3}[/tex]y=b <=> 3logx + 6logy =b (2)

(1),(2)=> logx= [tex]\frac{-3a+2b}{3}[/tex]

            logy= 3a-b

=> log[tex]\frac{y}{x}[/tex]=logy-logx=3a-b -( [tex]\frac{-3a+2b}{3}[/tex]) = [tex]\frac{12a-5b}3}[/tex]

   log[tex]\sqrt{xy}[/tex] = [tex]\frac{1}{2}[/tex](logx+logy)=........ OK

Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.