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Please solve this for me with full steps please it’s urgent
Don’t spam or write unnecessary things or else I’ll report

Please Solve This For Me With Full Steps Please Its Urgent Dont Spam Or Write Unnecessary Things Or Else Ill Report class=

Sagot :

Answer:

Step-by-step explanation:

logx[tex]y^{2}[/tex] <=> logx + 2logy = a (1)

log[tex]x^{3}[/tex]y=b <=> 3logx + 6logy =b (2)

(1),(2)=> logx= [tex]\frac{-3a+2b}{3}[/tex]

            logy= 3a-b

=> log[tex]\frac{y}{x}[/tex]=logy-logx=3a-b -( [tex]\frac{-3a+2b}{3}[/tex]) = [tex]\frac{12a-5b}3}[/tex]

   log[tex]\sqrt{xy}[/tex] = [tex]\frac{1}{2}[/tex](logx+logy)=........ OK

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