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Little's law can be applied to any part of the store, such as a particular department or the checkout lines. The store owner determines that, during business hours, approximately 84 shoppers per hour make a purchase and each of these shoppers spend an average of 5 minutes in the checkout line. At any time during business hours, about how many shoppers, on average, are waiting in the checkout line to make a purchase at the Good Deals Store?​

Sagot :

Given,

Number of shoppers per hour (during business hours) = 84

Time spent by each shopper (average) = 5 minutes.

Now,

→ 60 mins (1 hour) = 84 shoppers

→ 60 = 84

→ 84/60

→ 1.4

→ 1.4 × 5 = 7

→ 7 shoppers on an average, are waiting in the checkout line to purchase at the "Good Deals store"

The number of shoppers, on average waiting in the checkout line to make a purchase at the Good Deals Store is 7 shoppers.

The given parameters:

  • Number of shoppers per hour = 84
  • Time spent in the checkout line = 5 mins

The average number of shoppers per minute at the Good deals store is calculated as follows;

[tex]n = \frac{84 \ }{hr} \times \frac{1 \ hr}{60 \min} \\\\n = 1.4 \ shoppers/ \min[/tex]

The number of shoppers, on average waiting in the checkout line to make a purchase at the Good Deals Store is calculated as follows;

[tex]number \ of \ shoppers = 1.4 \ \frac{shoppers}{\min} \ \times \ 5 \min\\\\number \ of \ shoppers = 7 \ shoppers[/tex]

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