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Consider an automobile moving at v mph that skids d feet after its brakes lock. Calculate how far it would skid if it was moving at 2v and the brakes were locked.

Sagot :

Answer:

KE1 = 1/2 M V^2

KE2 = 1/2 M (2*V)^2

KE2 = 4 KE1

If stopping distance is proportional to the original KE then the stopping distance is 4 times great for the car moving at 2 * V