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find the 5th term of the geometric progression of,4/3, 18/9, 1, 16/27.​

Sagot :

abidemiokin

The fifth term of the geometric progression is 6.75

Given the geometric progression 4/3, 18/9, 1, 16/27.​..

The nth term of a geometric progression is expressed according to the equation [tex]a_n=ar^{n-1}[/tex]

  • a is the first term of the sequence
  • n is the number of terms
  • r is the common ratio

Given the following parameters;

a = 4/3

r = 18/9 * 3/4 = 3/2

n = 5

Substitute the given values into the formula

[tex]a_5=\frac{4}{3}(\frac{3}{2} )^{5-1}\\a_5 =\frac{4}{3}(\frac{3}{2} )^{4}\\a_5=\frac{4}{3}(5.0625)\\a_5=6.75[/tex]

Hence the fifth term of the geometric progression is 6.75

Learn more on GP here: https://brainly.com/question/25274096

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