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solve the following equation simultaneously 2a-3b+10=0, 10a+6b=8​

Sagot :

loneguy

[tex]2a -3b +10 =0\\\\10a+ 6b -8 =0\\\\\text{Using cross multiplication method}\\\\\\ \dfrac a{(-3)(-8) - 6(10)} = \dfrac b{10(10) - 2(-8)} = \dfrac 1{ 2(6) - (-3)(10)}\\\\\\\implies \dfrac a{24-60} = \dfrac b{100+16} = \dfrac 1{12+30}\\\\\\\\\implies -\dfrac {a}{36} = \dfrac b{116} = \dfrac 1{42}\\\\\\\text{Hence}\\\\a = - \dfrac{36}{42} = -\dfrac 67 \\\\\\ b= \dfrac{116}{42} = \dfrac{58}{21}[/tex]

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