At Westonci.ca, we connect you with the best answers from a community of experienced and knowledgeable individuals. Get accurate and detailed answers to your questions from a dedicated community of experts on our Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

The perpendicular bisector of the line segment joining the points A (-8, 0) and B (8, 0) passes through a point (0,k). the value of k is

Sagot :

The steepness of a line is determined by its slope. The value of "k" is 0

First, we need to find the slope of the line passing through the points A (-8, 0) and B (8, 0) as shown:

[tex]m=\frac{y_2-y_1}{x_2-x_1}\\m=\frac{0-0}{8-(-8)}\\m=\frac{0}{16}\\m =0[/tex]

To get the value of k, we will equate the slope of the perpendicular line which is 0 to the slope of the line passing through A (-8, 0)  and (0, k)

[tex]m=\frac{y_2-y_1}{x_2-x_1}\\m=\frac{k-0}{0-8}\\m=\frac{k}{-8}\\0=\frac{k}{-8}\\k = 0[/tex]

Hence the value of "k" is 0

Learn more on  slope here: https://brainly.com/question/16949303