Answered

Discover answers to your most pressing questions at Westonci.ca, the ultimate Q&A platform that connects you with expert solutions. Discover detailed solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

The perpendicular bisector of the line segment joining the points A (-8, 0) and B (8, 0) passes through a point (0,k). the value of k is

Sagot :

abidemiokin

The steepness of a line is determined by its slope. The value of "k" is 0

First, we need to find the slope of the line passing through the points A (-8, 0) and B (8, 0) as shown:

[tex]m=\frac{y_2-y_1}{x_2-x_1}\\m=\frac{0-0}{8-(-8)}\\m=\frac{0}{16}\\m =0[/tex]

To get the value of k, we will equate the slope of the perpendicular line which is 0 to the slope of the line passing through A (-8, 0)  and (0, k)

[tex]m=\frac{y_2-y_1}{x_2-x_1}\\m=\frac{k-0}{0-8}\\m=\frac{k}{-8}\\0=\frac{k}{-8}\\k = 0[/tex]

Hence the value of "k" is 0

Learn more on  slope here: https://brainly.com/question/16949303

We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.