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a woman spent two thirds of her money. she lost two thirds of the remiander and then had $4(aus money) left. how much money did she start with?​

Sagot :

The initial amount of money she had before the spending and loss is; $36

How to solve algebra word problems?

We are told that she spent ²/₃ of her money.

Let the initial amount be x. Thus;

Amount spent = ²/₃x

Amount left = ¹/₃x

She lost ²/₃ of amount left. Thus;

Amount lost = ²/₃ *  ¹/₃x = ²/₉x

She has $4 left after the loss. Thus;

¹/₃x - ²/₉x = 4

Multiply through by 9 to get;

3x - 2x = 36

x = $36

Thus, she started with $36

Read more about Algebra word problems at; https://brainly.com/question/13818690

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