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What is the length of leg s of the triangle below?

What Is The Length Of Leg S Of The Triangle Below class=

Sagot :

Answer:

D

Step-by-step explanation:

Using the sine ratio in the right triangle and the exact value

sin45° = [tex]\frac{1}{\sqrt{2} }[/tex] , then

sin45° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{s}{\sqrt{32} }[/tex] = [tex]\frac{1}{\sqrt{2} }[/tex] ( cross- multiply )

s × [tex]\sqrt{2}[/tex] = [tex]\sqrt{32}[/tex] ( divide both sides by [tex]\sqrt{2}[/tex] )

s = [tex]\frac{\sqrt{32} }{\sqrt{2} }[/tex] = [tex]\sqrt{\frac{32}{2} }[/tex] = [tex]\sqrt{16}[/tex] = 4 → D

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