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Sagot :
Clear the absolute-value bars by splitting the equation into its two cases, one for the Positive case and the other for the Negative case.
The Absolute Value term is |2x-2|
For the Negative case we'll use -(2x-2)
For the Positive case we'll use (2x-2)
-(2x-2) < 8
Multiply
-2x+2 < 8
Rearrange and Add up
-2x < 6
Divide both sides by 2
-x < 3
Multiply both sides by (-1)
Remember to flip the inequality sign
x > -3
Which is the solution for the Negative Case
(2x-2) < 8
Rearrange and Add up
2x < 10
Divide both sides by 2
x < 5
Which is the solution for the Positive Case
[tex] -3 < x < 5[/tex]
[tex]( - 3,5)[/tex]
One solution was found :
-3 < x < 5
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