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Given: triangle ABC,
BC=6cm,
CD is perpendicular to AB,
measurement of ACB=90 degrees,
measurement of ACD=60 degrees,
Find: AD

Given Triangle ABC BC6cm CD Is Perpendicular To AB Measurement Of ACB90 Degrees Measurement Of ACD60 Degrees Find AD class=

Sagot :

Answer:

9cm

Step-by-step explanation:

JUST TRUST ME!!!!!

The value of AD in triangle ABC is approximately 9 cm.

BC = 6cm

Using trigonometric ratio for triangle CBD

sin 60° = opposite / hypotenuse

0.86602540378  =  DC / 6

cross multiply

DC = 6 × 0.86602540378

DC = 5.19615242271

DC = 5.20 cm

Let's find side AD as follows:

tan 60° = AD / adjacent

AD = 5.20 × tan 60°

AD = 9.00666419936

AD ≈ 9 cm

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