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Sagot :
Answer:
A = 502 * e^-(.033 * 68) amount left after 68 rears
A = 502 e^-2.244 = 53.2 grams after 68 years
A2 = 502 e^-(.033 * T) = 251 where T is time for 1 half-life
ln (1/2) = -(.033 * T)
T = -.693 / -.033 = 21.0 years for the half-life
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