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Ada, Betty, Chris, and David have $45 in total. If
Ada gets $2 from Betty, Chris triples his money,
and David 's money is cut by half, four of them
have the same amount. Initially Ada has $

Sagot :

The initial amount of money Ada have is $9.25 and this can be determined by forming the linear equation.

Given :

  • Ada, Betty, Chris, and David have $45 in total.
  • Ada gets $2 from Betty, Chris triples his money,  and David's money is cut by half, four of them have the same amount.

The linear equation can be formed in order to determine the initial amount Ada has.

According to the given data, Ada, Betty, Chris, and David have $45 in total. So, let the initial amount Ada have to be 'w', Betty be 'x', Chris be 'y', and David be 'z'.

Then the linear equation that represents the total amount of money all of them have is $45 is given by:

w + x + y + z = 45   --- (1)

It is also given that Ada gets $2 from Betty, Chris triples his money,  and David's money is cut by half, four of them have the same amount. So, let 'a' be the amount that all of them have so, equation (1) becomes:

4a = 45

a = $11.25  

Now, the initial amount of money Ada have is:

a = x + 2

11.25 = x + 2

x = $9.25

For more information, refer to the link given below:

https://brainly.com/question/19770987

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