Answered

Looking for trustworthy answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

A 2.00 kg cat is in a 97.00 kg elevator. What force on the elevator cable would be needed to lower the cat/elevator pair with an acceleration of 2.00 m/s^2 downwards?

Sagot :

Lanuel

The magnitude of force on the elevator cable that would be needed to lower the cat/elevator pair is 198 Newton.

Given the following data:

  • Mass of cat = 2 kg
  • Mass of elevator = 97 kg
  • Acceleration = 2 [tex]m/s^2[/tex]

To determine the magnitude of force on the elevator cable that would be needed to lower the cat/elevator pair, we would apply Newton's Second Law of Motion:

First of all, we would calculate the total mass of the cat/elevator pair.

[tex]Total \;mass=2 + 97[/tex]

Total mass = 99 kilograms

Mathematically, Newton's Second Law of Motion is given by this formula;

[tex]Force = mass \times acceleration[/tex]

Substituting the given parameters into the formula, we have;

[tex]Force = 99 \times 2[/tex]

Net force = 198 Newton

Read more here: https://brainly.com/question/24029674

Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.