kiribaku176
Answered

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Help, please! This is due tomorrow evening! Show work, please! Will give brainliest!

Help Please This Is Due Tomorrow Evening Show Work Please Will Give Brainliest class=
Help Please This Is Due Tomorrow Evening Show Work Please Will Give Brainliest class=
Help Please This Is Due Tomorrow Evening Show Work Please Will Give Brainliest class=
Help Please This Is Due Tomorrow Evening Show Work Please Will Give Brainliest class=

Sagot :

Answer:

h = height reached

-16 t^2 = 1/2 g t^2 where g = 32 ft/sec^2

v t = height due to original vertical speed v

s = initial height

1. -45 = -16 t^2 + 62 t + 0         measuring height from original height

solving quadratic

2. t = 4.5 sec

3. time to reach max height = v / g = 62/32 = 1.94 sec

H (above release point) = -16 (1.94^2) + 62 * 1.94 = 60 ft

4. 2 * 1.94 = 3.88    solved in part 3

5. 1.94   solved on part 3

Check:  time to fall 60 + 45 ft = 105 ft

105 = 1/2 g t^2

t = (210 / 32)^1/2 = 2.56 sec

total time = 2.56 * 1.94 = 4.5 sec     time to fall + rise time

-45 = -16 * 4.5^2 + 62 * 4.5

-45 = -324 + 279 = -45        checking time to reach -45 feet using given equation

scunningham084

Answer:

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Step-by-step explanation:

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