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Sagot :
The ladder reaches 17.2-foot high up the wall.
Given that,
Ajay leans à 18-foot ladder against a wall so that it forms an angle of 73° with the ground.
We have to find,
How high up the wall does the ladder reach?
According to the question,
Ajay leans à 18-foot ladder against a wall so that it forms an angle of 73° with the ground.
Let, the height of the wall does the ladder reach is y,
Then,
[tex]\rm Sin\theta = \dfrac{Opposite \ side}{Hypotenuse}[/tex]
Here, Angle = 17 degree, opposite side = y, and perpendicular = 18
Therefore,
[tex]\rm Sin73 = \dfrac{y}{18}\\\\0.95 = \dfrac{y}{18}\\\\y = 18 \times 0.95\\\\y = 17.2 \ foot[/tex]
Hence, The ladder reaches 17.2-foot high up the wall.
For more details refer to the link.
https://brainly.com/question/2016644
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