Discover the best answers at Westonci.ca, where experts share their insights and knowledge with you. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
[tex]7 \tan^3 x - 21\tan x =0\\\\\implies 7\tan x(7 \tan^2 x -21) = 0\\\\\implies 7 \tan x = 0 ~~\text{or}~~ 7\tan^2 x -21 =0\\\\\implies \tan x = 0 ~~\text{or}~~ \tan x = \pm\sqrt{\dfrac{21}7} = \pm \sqrt 3\\\\\text{Now,}\\\\\tan x = 0\\\\\implies x = n \pi \\\\\implies x = 0, \pi ~~~~~~~~~~~~~;[\text{For n=0,1 and}~ [0, 2 \pi)}]\\\\\\\tan x = \sqrt 3 \\\\\implies x = n \pi + \dfrac{\pi}3\\\\\implies x = \dfrac{\pi}3, ~~\dfrac{4 \pi}{3} ~~~~~~~~;[\text{For n = 0,1 and }~ [0, 2\pi)]\\\\\\[/tex]
[tex]\tan x = -\sqrt 3\\\\\implies x= n\pi - \dfrac{\pi}3\\\\\implies x = \dfrac{2\pi}{3},~~ \dfrac{5\pi}3 ~~~~~~~ ;[\text{For n=1,2 and}~ [0,2\pi)][/tex]'
[tex]\text{Combine all solutions,}\\\\x= 0, ~\pi, ~\dfrac{\pi}3,~ \dfrac{4 \pi}3 ,~ \dfrac{2 \pi}3 , ~\dfrac{5\pi}3[/tex]
We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.