Answered

Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Get immediate and reliable solutions to your questions from a community of experienced experts on our Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.


A bag contains 7 marbles: 4 red, 2 yellow, and 1 green. Three
marbles are to be selected from the bag, one at a time, without
replacement. If the order of selection does not matter, how many
color combinations of the three marbles are possible?

Sagot :

121159

Answer:

Step-by-step explanation:

you have 7 reds of 14 total.

the 1st marble has 7 of 14 probability of being red

the 2nd has 6 of 13 of being red

the 3rd has 5 of 12 of being red

multiplying this out you have:

(7/14)*(6/13)*(5/12)=210/2184

THAT will condense down to 5/52 or 9.615%

this does assume not placing the balls back in between draws

if you do put them back in between draws you would have 7 of 14 chance each draw

that would give you by multiplying out

(7/14) * (7/14)* (7/14) = 343/2744

Found it online lol

that condenses to 1 of 8 or 12.5%

Found it online lol

Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.