lowerylanden57
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Use your knowledge about parentheses and substitution to solve the following:

q = 1; r = 2; s = 3; t = 4; x = 5; y = 6

7. 2(x + 4) + 10 =

8. 3(6x) + 4 =

9. 10(xy) =

10. 5(x + y) =

11. 2(rs) + 4(x)

12. 2(q) + 2(x + t) =

13. 6(7t + 4s) =

14. 9(10x) + 10y =

15. 2x(xy) =

16. r(s)(t) =

17. (r)(s)(t)(x)(y) =

18. (7x + 2Y) =

Sagot :

22phamvn

Answer:

16. r(s)(t) =

r=2, s=3, t=4

(2)(3)(4)=

             (2*3) = 6  ---> 6(4) = 24

final: 24

17. (r)(s)(t)(x)(y) =

r = 2, s = 3, t = 4, x = 5, y = 6

(2)(3)(4)(5)(6)

2*3=6

      6*4=24

            24*5= 120

                     120*6=720

final: 720

18. (7x + 2Y) =

x = 5, y = 6

rewrite--->        = [7(5) + 2(6)]

[35 + 12] = 47

final: 47

hope this helpsss sorry took a while LOL

Step-by-step explanation:

q = 1; r = 2; s = 3; t = 4; x = 5; y = 6
Answers:

7. 2(5 + 4) + 10 =
2 x 9 + 10
18 + 10
= 28

8. 3(6(5)) + 4 =
3 x 30 + 4
90 + 4
= 94

9. 10(5)(6) =
50 x 6
= 300

10. 5(5 + 6) =
5 x 11
= 55

11. 2(2)(3) + 4(5) =
12 + 4 x 5
12 + 20
= 32

12. 2(1) + 2(5 + 4) =
2 + 2(5 + 4)
2 + 2 x 9
2 + 18
= 20

13. 6(7(4) + 4(3)) =
6(28 + 4 x 3)
6(28 + 12)
6 x 40
= 240

14. 9(10(5)) + 10(6) =
9 x 50 + 10 x 6
9 x 50 + 60
450 + 60
= 510

15. 2(5)(5(6)) =
2 x 5 x 30
= 300

16. 2(3)(4) =
6 x 4
= 24

17. (2)(3)(4)(5)(6) =
10 x 3 x 4 x 6
30 x 4 x 6
120 x 6
= 720

18. (7(5) + 2(6)) =
35 + 2 x 6
35 + 12
= 47
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