anwindiya4
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Geometry RSM question help

Geometry RSM Question Help class=

Sagot :

[tex]\textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\[-0.35em] ~\dotfill\\\\ \sqrt{20^2-16^2}=PQ\implies 12=PQ \\\\\\ PS=\sqrt{12^2+5^2}\implies \boxed{PS=13}[/tex]

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View image jdoe0001

Answer:

PS=13

Step-by-step explanation:

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