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If (k+1), 3k, (4k+2) are three consecutive terms of an AP then k = ?​

Sagot :

SalmonWorldTopper

The three consecutive terms in an AP are (k+1) ,3k and (4k+2)

We know that

If a,b,c are the three consecutive terms in an AP then b = (a+c)/2

now ,

Let a = k+1 , b = 3k and c = 4k+2

⇛3k = (k+1+4k+2)/2

⇛3k = (5k+3)/2

⇛2×3k = 5k+3

⇛6k = 5k+3

⇛ 6k-5k = 3

⇛ k = 3

The value of k = 3

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