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The 11th term of the AP -3, -1/2, 2 . .... is​

Sagot :

Given AP is -3 ,-1/2,2,..

First term = -3

Common difference = (-1/2)-(-3)

⇛d = (-1/2)+3

⇛d = (-1+6)/2

⇛ d = 5/2

We know that nth term = an = a+(n-1)d

11th term = (-3)+(11-1)(5/2)

⇛a 11 = -3+(10)(5/2)

⇛a 11 = -3+(5×5)

⇛a 11 = -3+25

⇛ a 11 = 22

11th term of the AP = 22.

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IPv4

Answer:

2

Step-by-step explanation:

initial term = -3

common difference = .5

-3 + .5 for 11 times from 3 = positive 2