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a
Joshua is flying a kite, holding his hands a distance of 3.75 feet above the
ground and letting all the kite's string play out. He measures the angle of
elevation from his hand to the kite to be 28°. If the string from the kite to his
hand is 140 feet long, how many feet is the kite above the ground? Round
your answer to the nearest hundredth of a foot if necessary.

Sagot :

Answer:

Step-by-step explanation:

Assuming the ground is level

h = 3.75 + 140sin28

h = 69.47601...

h = 69.48 ft.

The height of the kite above the ground is 69.48 ft

Right angle triangle:

  • A right angle triangle is a triangle that has one of its angle as 90 degrees. Therefore,

Using trigonometric ratio, the opposite side of the triangle formed can be calculated as follows:

  • sin 28° = opposite / hypotenuse

sin 28° = x / 140

x = 140 sin 28

x = 140 × 0.46947156278

x = 65.72601879

x = 65.73

The height of the kite from the ground = 65.73 + 3.75 = 69.48 feet

learn more on right triangle here: https://brainly.com/question/25892318

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