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Sagot :
- Let the breadth of the rectangle be x cm
- lenght of the rectangle = ( x + 5 ) cm
perimeter of the rectangle = 2 ( l + b )
- 2 ( x + x + 5 ) cm
- 2 ( 2x + 5') cm
- ( 4x + 10 ) cm
4x + 10 = 40
4x = 40 10 ( transpose 10 to RHS )
x = 30/4 = 7.5 ( divide both sides by 4 )
- lenght of the rectangle = x + 5 = 7.5 + 5 = 12.5 cm
- breadth of the rectangle = x = 7.5 cm
- Breadth be x
- Length be x+5
ATQ
[tex]\\ \sf\longmapsto 2(x+x+5)=40[/tex]
[tex]\\ \sf\longmapsto 2(2x+5)=40[/tex]
[tex]\\ \sf\longmapsto 2x+5=20[/tex]
[tex]\\ \sf\longmapsto 2x=15[/tex]
[tex]\\ \sf\longmapsto x=7.5[/tex]
- Length=12.5cm
- Breadth=7.5cm
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