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Solve 2/3 (3x+14)=7x+6 by first multiplying both sides of the equation by 3 before applying the distributive property

Sagot :

loneguy

[tex]\dfrac23 (3x +14) =7x+6\\\\\\\implies 3\left[\dfrac 23 (3x+14) \right] = 3(7x+6)\\\\\\\implies 2(3x+14) = 21x +18\\\\\implies 6x + 28 =21x +18\\\\\implies 21x -6x = 28-18\\\\\implies 15x = 10\\\\\implies x = \dfrac{10}{15} = \dfrac 23[/tex]

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