Part A: The approximate volume of the frustum is [tex]1769cm^3[/tex].
Part B: How the answer was determined was to view the flower pot as a frustum of a cone, and apply the formula in calculating the volume of the flower-pot.
The flower pot has the shape of a conical frustum (See the attached image). The volume of the frustum is given by
[tex]F = \frac{\pi y}{3}(R^2+Rr+r^2)[/tex]
where
[tex]y=\text{height of the frustum}=H-h=10cm\\R=\text{radius of larger cone}=8cm\\r=\text{radius of smaller cone}=7cm[/tex]
substituting the values of [tex]y[/tex], [tex]R[/tex] and [tex]r[/tex] into the frustum formula and using [tex]\pi\approx 3.14[/tex]
[tex]F = \frac{\pi y}{3}(R^2+Rr+r^2)\\\\=\frac{\pi\times 10 }{3}(8^2+8\times 7+7^2)\\\\=\frac{10\pi}{3}(64+56+49)\\\\=\frac{1690\pi}{3}\\\\\approx 1769cm^3[/tex]
the approximate volume of the frustum is [tex]1769cm^3[/tex]
Learn more about the volume of a frustum here: https://brainly.com/question/14177094
