rafiahaider04
Answered

Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Ask your questions and receive precise answers from experienced professionals across different disciplines. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

Consider the equation of a circle x^2-2x+y^2-4y-4=0. If the line 2x-y+a=0 is its diameter. Then find the value of a.

Sagot :

Answer:

a=0

Step-by-step explanation:

x²-2x+y²-4y-4=0

(x²-2x+1)+(y²-4y+4)-9=0

(x-1)² + (y-2)² = 3²

Center: (1,2)     radius: 3

(1,2) on line 2x-y+a=0

2*1 - 2 + a = 0

a = 0

Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.