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Sagot :
Circle theorem states that the angle that an arc subtends at the center of a
circle is twice the angle subtended at the circumference.
The values are as follows;
- m∠EDA = 90°
- m∠BDC = 21°
- m∠BEC = 21°
- [tex]m\widehat{AB}[/tex] = 80°
- m∠AEB = 40°
- m∠ECA = 29°
- m∠BAC = 21°
- [tex]m\widehat{ED}[/tex] = 90°
- m∠ECD = 45°
- m∠ACB = 40°
- m∠EBD = 45°
- m∠ADB = 40°
- m∠CAD = 45°
- m∠EAB = 90°
- m∠EBC = 90°
Reasons:
[tex]\displaystyle 1. \ \mathbf{m\angle EDA} = \frac{1}{2} \cdot m\angle EPC[/tex] Angle subtended at center is twice angle at circumference.
m∠EPC = 180°
∴ m∠EDA = 0.5 × 180° = 90°
2. [tex]m\widehat{BC}[/tex] = 42°, therefore, m∠BPC = 42°
[tex]\displaystyle \ m\angle BDC= \frac{1}{2} \cdot m\angle BPC[/tex]
m∠BDC = 0.5 × 42° = 21°
3. m∠BEC = m∠BDC = 21°
4. [tex]m\widehat{AB}[/tex] = 180° - (58° + 42°) = 80°
5. [tex]\mathbf{m\widehat{AB}}[/tex] = m∠APB by definition
m∠AEB = 0.5 × m∠APB
m∠AEB = 0.5 × 80° = 40°
6. m∠ECA = 0.5 × m∠AE
Therefore;
m∠ECA = 0.5 × [tex]m\widehat{EA}[/tex]
m∠ECA = 0.5 × 58° = 29°
m∠ECA = 29°
7. m∠BAC = 0.5 × [tex]\mathbf{m\widehat{BC}}[/tex]
m∠BAC = 0.5 × 42° = 21°
m∠BAC = 21°
8. [tex]m\widehat{ED}[/tex] = 180° - [tex]\mathbf{m\widehat{CD}}[/tex]
[tex]m\widehat{ED}[/tex] = 180° - 90° = 90°
[tex]\mathbf{m\widehat{ED}}[/tex] = 90°
9. m∠ECD = 0.5 × [tex]\mathbf{m\widehat{ED}}[/tex]
m∠ECD = 0.5 × 90° = 45°
10. m∠ACB = 0.5 × [tex]m\widehat{AB}[/tex]
m∠ACB = 0.5 × 80° = 40°
11. m∠EBD = 0.5 × [tex]\mathbf{m\widehat{ED}}[/tex]
m∠EBD = 0.5 × 90° = 45°
12. m∠ADB = 0.5 × [tex]\mathbf{m\widehat{AB}}[/tex]
m∠ADB = 0.5 × 80° = 40°
13. m∠CAD = 0.5 × [tex]\mathbf{m\widehat{CD}}[/tex]
m∠CAD = 0.5 × 90° = 45°
14. m∠EAB = 0.5 ×[tex]\mathbf{m\widehat{EABC}}[/tex]
m∠EAB = 0.5 × 180° = 90°
15. m∠EBC = 0.5 ×[tex]\mathbf{m\widehat{EABC}}[/tex]
m∠EBC = 0.5 × 180° = 90°
Learn more about circle theorems here:
https://brainly.com/question/25101481
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