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My Question Is In The Attachment class=

Sagot :

Answer:

5 and 25

Step-by-step explanation:

let the son's age be x then the father's age is x + 20

In 5 years

son = x + 5 and father = x + 20 + 5 = x + 25

Then

x + 25 = 3(x + 5) ← father is three times as old as son

x + 25 = 3x + 15 ( subtract x from both sides )

25 = 2x + 15 ( subtract 15 from both sides )

10 = 2x ( divide both sides by 2 )

5 = x and x + 20 = 5 + 20 = 25

si=on is 5 and father is 25

Answer:

The son is 5 and the father is 25.

Step-by-step explanation:

We can do this using  Algebra.

Let the son be x years old.

Then the father's age is x + 20 years.

After 5 years the father's age is x + 25 and the son is x + 5 years.

So we can write the equation:

x + 25 = 3(x + 5)

x + 25 = 3x + 15

25 - 15 = 3x - x

10 = 2x

x = 5.

So the father's present age is 20 + 5 = 25 and the son is 5 years old.

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