Answer:
[tex]\huge\boxed{x=29;\ y=51}[/tex]
Step-by-step explanation:
This is Isosceles triangle (look at the picture).
We know:
All triangles have internal angles that add up to 180°
Therefore:
[tex](x-2)+(x-2)+(4x+10)=180[/tex]
combine like terms:
[tex](x+x+4x)+(-2-2+10)=180\\\\6x+6=180\qquad|\text{subtract 6 from both sides}\\\\6x=174\qquad|\text{divide both sides by 6}\\\\x=29[/tex]
(x - 2)° and 3y° are supplementary angle (Two Angles are Supplementary when they add up to 180°).
Therefore:
[tex]3y+(x-2)=180[/tex]
substitute x = 29 and solve for y:
[tex]3y+(29-2)=180\\\\3y+27=180\qquad|\text{subtract 27 from both sides}\\\\3y=153\qquad|\text{divide both sides by 3}\\\\y=51[/tex]
