Answer: The products will be copper and oxygen.
Explanation: Copper electorde is an active electrode so it constantly takes part in the electrolysis. Cathode is a pure copper negative electrode and anode is a impure copper positive electrode. So the copper present in the solution, along with the copper present in the anode will come off and go to the cathode. As a result, cathode gains copper. And the remaining impurities settle down in the bottom.
In the anode, oxygen will be given off because according to the order of discharge, if SO4 is present then the ions will stay in the solution and oxygen will be released. So at the end, solution of SO4 and H2O will be remaining while copper and oxygen is extracted.
The half equations are-
Cathode: Cu2+ + 2e- = Cu
Anode: Cu + 2e- = Cu2+
Something you might not know: The solution in electrolysis turns blue when copper goes to the cathode. So copper electrodes are also used in electroplating.
